^2+a^2=(4R)^2

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Solution for ^2+a^2=(4R)^2 equation: 



^2+a^2=(4)^2

We move all terms to the left:

^2+a^2-((4)^2)=0

determiningTheFunctionDomain
a^2+^2-4^2=0

We add all the numbers together, and all the variables

a^2=0

a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$a=\frac{-b}{2a}=\frac{0}{2}=0$

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